Which of the following species would not be i | vedclass

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(D) The Hoffmann rearrangement involves the following steps:$1$. Formation of $N$-bromamide by the reaction of amide with $Br_2$ and $NaOH$.$2$. Forma

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All of the above are involved in the reaction.

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(D) The Hoffmann rearrangement involves the following steps:$1$. Formation of $N$-bromamide by the reaction of amide with $Br_2$ and $NaOH$.$2$. Formation of an acyl nitrene or direct rearrangement of the $N$-bromoamide anion to an isocyanate.$3$. The isocyanate is then hydrolyzed to the amine.Looking at the provided mechanism in the solution image,the species involved are:$(a)$ $N$-bromocyclohexanecarboxamide$(b)$ The conjugate base of the $N$-bromoamide$(c)$ Cyclohexyl isocyanateSince all these species are intermediates or products in the mechanism of the Hoffmann rearrangement,option $D$ is the correct answer.

List-$I$	List-$II$
$1.$ Aniline	$a.$ Used in the preparation of azo dyes
$2.$ Nitrobenzene	$b.$ Sulpha drug
$3.$ Sulphanilamide	$c.$ Solvent in Friedel-Crafts reaction
$4.$ Trinitrotoluene	$d.$ Used as an explosive

Which of the following species would not be involved in the Hoffmann rearrangement shown below?

Similar Questions

In which of the following reactions is a tertiary amine formed?

Amine compounds exhibit ............ isomerism.

Match List-$I$ with List-$II$ and select the correct answer.

List-$I$ List-$II$

$1.$ Aniline $a.$ Used in the preparation of azo dyes

$2.$ Nitrobenzene $b.$ Sulpha drug

$3.$ Sulphanilamide $c.$ Solvent in Friedel-Crafts reaction

$4.$ Trinitrotoluene $d.$ Used as an explosive

The compounds $X$ and $Y$ are respectively:

Which of the following reactions will not give a primary amine?

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